Base | Representation |
---|---|
bin | 10010000011101101111… |
… | …111100101101110001001 |
3 | 11101122002111000220222012 |
4 | 102003231333211232021 |
5 | 130312423010413032 |
6 | 2350025340505305 |
7 | 155440510202624 |
oct | 22035577455611 |
9 | 4348074026865 |
10 | 1240943451017 |
11 | 439310254916 |
12 | 18060554b235 |
13 | 90035c681ba |
14 | 440c2122dbb |
15 | 2242e4336b2 |
hex | 120edfe5b89 |
1240943451017 has 2 divisors, whose sum is σ = 1240943451018. Its totient is φ = 1240943451016.
The previous prime is 1240943450983. The next prime is 1240943451029. The reversal of 1240943451017 is 7101543490421.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 984121536841 + 256821914176 = 992029^2 + 506776^2 .
It is a cyclic number.
It is not a de Polignac number, because 1240943451017 - 26 = 1240943450953 is a prime.
It is not a weakly prime, because it can be changed into another prime (1240943451817) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620471725508 + 620471725509.
It is an arithmetic number, because the mean of its divisors is an integer number (620471725509).
Almost surely, 21240943451017 is an apocalyptic number.
It is an amenable number.
1240943451017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240943451017 is an equidigital number, since it uses as much as digits as its factorization.
1240943451017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 41.
The spelling of 1240943451017 in words is "one trillion, two hundred forty billion, nine hundred forty-three million, four hundred fifty-one thousand, seventeen".
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