Base | Representation |
---|---|
bin | 1011010010011000011101… |
… | …0101010111001011011111 |
3 | 1121221102111021111022202012 |
4 | 2310212013111113023133 |
5 | 3111313030321323041 |
6 | 42221135011421435 |
7 | 2420424023216333 |
oct | 264460725271337 |
9 | 47842437438665 |
10 | 12410431042271 |
11 | 3a55263869699 |
12 | 14852842b487b |
13 | 6c03b6108192 |
14 | 30c94d2697c3 |
15 | 167c5546d3eb |
hex | b49875572df |
12410431042271 has 2 divisors, whose sum is σ = 12410431042272. Its totient is φ = 12410431042270.
The previous prime is 12410431042189. The next prime is 12410431042301. The reversal of 12410431042271 is 17224013401421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12410431042271 - 242 = 8012384531167 is a prime.
It is a super-3 number, since 3×124104310422713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12410431048271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6205215521135 + 6205215521136.
It is an arithmetic number, because the mean of its divisors is an integer number (6205215521136).
Almost surely, 212410431042271 is an apocalyptic number.
12410431042271 is a deficient number, since it is larger than the sum of its proper divisors (1).
12410431042271 is an equidigital number, since it uses as much as digits as its factorization.
12410431042271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 32.
Adding to 12410431042271 its reverse (17224013401421), we get a palindrome (29634444443692).
The spelling of 12410431042271 in words is "twelve trillion, four hundred ten billion, four hundred thirty-one million, forty-two thousand, two hundred seventy-one".
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