Base | Representation |
---|---|
bin | 1011010010011000011111… |
… | …1000011100101111111111 |
3 | 1121221102111220210121211112 |
4 | 2310212013320130233333 |
5 | 3111313040200141002 |
6 | 42221135540512235 |
7 | 2420424164335256 |
oct | 264460770345777 |
9 | 47842456717745 |
10 | 12410440240127 |
11 | 3a55268a81126 |
12 | 14852873ab67b |
13 | 6c03b7ca88b7 |
14 | 30c95058179d |
15 | 167c56188852 |
hex | b4987e1cbff |
12410440240127 has 2 divisors, whose sum is σ = 12410440240128. Its totient is φ = 12410440240126.
The previous prime is 12410440240103. The next prime is 12410440240181. The reversal of 12410440240127 is 72104204401421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12410440240127 - 210 = 12410440239103 is a prime.
It is a super-2 number, since 2×124104402401272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12410440240093 and 12410440240102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12410440242127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6205220120063 + 6205220120064.
It is an arithmetic number, because the mean of its divisors is an integer number (6205220120064).
Almost surely, 212410440240127 is an apocalyptic number.
12410440240127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12410440240127 is an equidigital number, since it uses as much as digits as its factorization.
12410440240127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14336, while the sum is 32.
Adding to 12410440240127 its reverse (72104204401421), we get a palindrome (84514644641548).
The spelling of 12410440240127 in words is "twelve trillion, four hundred ten billion, four hundred forty million, two hundred forty thousand, one hundred twenty-seven".
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