Base | Representation |
---|---|
bin | 1011010010011111111010… |
… | …1010110001010011110111 |
3 | 1121221121122210210120200012 |
4 | 2310213332222301103313 |
5 | 3111331130341034111 |
6 | 42222105411410435 |
7 | 2420524443620645 |
oct | 264477652612367 |
9 | 47847583716605 |
10 | 12412433143031 |
11 | 3a560a0a10619 |
12 | 14857428b3a1b |
13 | 6c0644b3979c |
14 | 30ca9d110195 |
15 | 167d210e848b |
hex | b49feab14f7 |
12412433143031 has 2 divisors, whose sum is σ = 12412433143032. Its totient is φ = 12412433143030.
The previous prime is 12412433143007. The next prime is 12412433143069. The reversal of 12412433143031 is 13034133421421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12412433143031 - 214 = 12412433126647 is a prime.
It is a super-2 number, since 2×124124331430312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12412433145031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6206216571515 + 6206216571516.
It is an arithmetic number, because the mean of its divisors is an integer number (6206216571516).
Almost surely, 212412433143031 is an apocalyptic number.
12412433143031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12412433143031 is an equidigital number, since it uses as much as digits as its factorization.
12412433143031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 12412433143031 its reverse (13034133421421), we get a palindrome (25446566564452).
The spelling of 12412433143031 in words is "twelve trillion, four hundred twelve billion, four hundred thirty-three million, one hundred forty-three thousand, thirty-one".
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