12412433143070 has 32 divisors (see below), whose sum is σ = 22379534958240. Its totient is φ = 4956718120960.

The previous prime is 12412433143069. The next prime is 12412433143127. The reversal of 12412433143070 is 7034133421421.

It is a self number, because there is not a number n which added to its sum of digits gives 12412433143070.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 65665814 + ... + 65854566.

It is an arithmetic number, because the mean of its divisors is an integer number (699360467445).

Almost surely, 2^{12412433143070} is an apocalyptic number.

12412433143070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12412433143070 is a deficient number, since it is larger than the sum of its proper divisors (9967101815170).

12412433143070 is a wasteful number, since it uses less digits than its factorization.

12412433143070 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 199660.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 12412433143070 its reverse (7034133421421), we get a palindrome (19446566564491).

The spelling of 12412433143070 in words is "twelve trillion, four hundred twelve billion, four hundred thirty-three million, one hundred forty-three thousand, seventy".