Base | Representation |
---|---|
bin | 10010000100000100100… |
… | …001000001011011111000 |
3 | 11101200001211001100120222 |
4 | 102010010201001123320 |
5 | 130314211224022130 |
6 | 2350131035435212 |
7 | 155453046035243 |
oct | 22040441013370 |
9 | 4350054040528 |
10 | 1241321314040 |
11 | 43949457aa05 |
12 | 1806abbb5b08 |
13 | 900963287a2 |
14 | 4411a3a425a |
15 | 224526c2ce5 |
hex | 121048416f8 |
1241321314040 has 64 divisors (see below), whose sum is σ = 2822436018720. Its totient is φ = 491296960000.
The previous prime is 1241321314039. The next prime is 1241321314043. The reversal of 1241321314040 is 404131231421.
It is a super-2 number, since 2×12413213140402 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1241321314043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6249050 + ... + 6444630.
Almost surely, 21241321314040 is an apocalyptic number.
1241321314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1241321314040 is an abundant number, since it is smaller than the sum of its proper divisors (1581114704680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1241321314040 is a wasteful number, since it uses less digits than its factorization.
1241321314040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197264 (or 197260 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 1241321314040 its reverse (404131231421), we get a palindrome (1645452545461).
The spelling of 1241321314040 in words is "one trillion, two hundred forty-one billion, three hundred twenty-one million, three hundred fourteen thousand, forty".
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