Base | Representation |
---|---|
bin | 10111000111110011… |
… | …01000101001100010 |
3 | 1012001010010200101102 |
4 | 23203321220221202 |
5 | 200410322040310 |
6 | 5411435434402 |
7 | 616421523341 |
oct | 134371505142 |
9 | 35033120342 |
10 | 12413471330 |
11 | 52a0098817 |
12 | 24a52b5a02 |
13 | 122aa11a10 |
14 | 85a8cbb58 |
15 | 4c9be58a5 |
hex | 2e3e68a62 |
12413471330 has 32 divisors (see below), whose sum is σ = 24457528368. Its totient is φ = 4508294400.
The previous prime is 12413471299. The next prime is 12413471387. The reversal of 12413471330 is 3317431421.
12413471330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 8 ways, for example, as 42915601 + 12370555729 = 6551^2 + 111223^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12413471293 and 12413471302.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 774761 + ... + 790620.
Almost surely, 212413471330 is an apocalyptic number.
12413471330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12413471330 is a deficient number, since it is larger than the sum of its proper divisors (12044057038).
12413471330 is a wasteful number, since it uses less digits than its factorization.
12413471330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1565462.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 12413471330 in words is "twelve billion, four hundred thirteen million, four hundred seventy-one thousand, three hundred thirty".
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