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124141027020119 is a prime number
BaseRepresentation
bin11100001110011111010101…
…110100010100110101010111
3121021112202200121200122100222
4130032133111310110311113
5112232411310404120434
61120005333413224555
735101615243115324
oct3416372564246527
9537482617618328
10124141027020119
1136611a0644837a
1211b0b44293215b
1354365aa7c50b5
14229265a17db4b
15e542d659e72e
hex70e7d5d14d57

124141027020119 has 2 divisors, whose sum is σ = 124141027020120. Its totient is φ = 124141027020118.

The previous prime is 124141027020097. The next prime is 124141027020121. The reversal of 124141027020119 is 911020720141421.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-124141027020119 is a prime.

It is a super-2 number, since 2×1241410270201192 (a number of 29 digits) contains 22 as substring.

Together with 124141027020121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124141027020019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62070513510059 + 62070513510060.

It is an arithmetic number, because the mean of its divisors is an integer number (62070513510060).

Almost surely, 2124141027020119 is an apocalyptic number.

124141027020119 is a deficient number, since it is larger than the sum of its proper divisors (1).

124141027020119 is an equidigital number, since it uses as much as digits as its factorization.

124141027020119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 35.

The spelling of 124141027020119 in words is "one hundred twenty-four trillion, one hundred forty-one billion, twenty-seven million, twenty thousand, one hundred nineteen".