Base | Representation |
---|---|
bin | 1011010010101010101111… |
… | …1101100010001100100011 |
3 | 1121221220011102112122102002 |
4 | 2310222223331202030203 |
5 | 3111403104133121402 |
6 | 42223310110514215 |
7 | 2420656466125211 |
oct | 264525375421443 |
9 | 47856142478362 |
10 | 12415340520227 |
11 | 3a57353069097 |
12 | 148621450596b |
13 | 6c09b9291318 |
14 | 30cc972c5cb1 |
15 | 167e41493602 |
hex | b4aabf62323 |
12415340520227 has 2 divisors, whose sum is σ = 12415340520228. Its totient is φ = 12415340520226.
The previous prime is 12415340520217. The next prime is 12415340520293. The reversal of 12415340520227 is 72202504351421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12415340520227 - 228 = 12415072084771 is a prime.
It is a super-2 number, since 2×124153405202272 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12415340520217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6207670260113 + 6207670260114.
It is an arithmetic number, because the mean of its divisors is an integer number (6207670260114).
Almost surely, 212415340520227 is an apocalyptic number.
12415340520227 is a deficient number, since it is larger than the sum of its proper divisors (1).
12415340520227 is an equidigital number, since it uses as much as digits as its factorization.
12415340520227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 134400, while the sum is 38.
Adding to 12415340520227 its reverse (72202504351421), we get a palindrome (84617844871648).
The spelling of 12415340520227 in words is "twelve trillion, four hundred fifteen billion, three hundred forty million, five hundred twenty thousand, two hundred twenty-seven".
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