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12415340520293 is a prime number
BaseRepresentation
bin1011010010101010101111…
…1101100010001101100101
31121221220011102112122111112
42310222223331202031211
53111403104133122133
642223310110514405
72420656466125334
oct264525375421545
947856142478445
1012415340520293
113a57353069147
121486214505a05
136c09b9291369
1430cc972c5d1b
15167e41493648
hexb4aabf62365

12415340520293 has 2 divisors, whose sum is σ = 12415340520294. Its totient is φ = 12415340520292.

The previous prime is 12415340520227. The next prime is 12415340520391. The reversal of 12415340520293 is 39202504351421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7271344150849 + 5143996369444 = 2696543^2 + 2268038^2 .

It is a cyclic number.

It is not a de Polignac number, because 12415340520293 - 210 = 12415340519269 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12415340520293.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12415340520893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6207670260146 + 6207670260147.

It is an arithmetic number, because the mean of its divisors is an integer number (6207670260147).

Almost surely, 212415340520293 is an apocalyptic number.

It is an amenable number.

12415340520293 is a deficient number, since it is larger than the sum of its proper divisors (1).

12415340520293 is an equidigital number, since it uses as much as digits as its factorization.

12415340520293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 41.

The spelling of 12415340520293 in words is "twelve trillion, four hundred fifteen billion, three hundred forty million, five hundred twenty thousand, two hundred ninety-three".