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12416201341 is a prime number
BaseRepresentation
bin10111001000001000…
…00011001001111101
31012001022021101020221
423210010003021331
5200412021420331
65412014141341
7616453653505
oct134404031175
935038241227
1012416201341
1152a1692925
1224a61b1851
13122b4594cb
1485addca05
154ca084711
hex2e410327d

12416201341 has 2 divisors, whose sum is σ = 12416201342. Its totient is φ = 12416201340.

The previous prime is 12416201327. The next prime is 12416201383. The reversal of 12416201341 is 14310261421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9046863225 + 3369338116 = 95115^2 + 58046^2 .

It is an emirp because it is prime and its reverse (14310261421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12416201341 - 25 = 12416201309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12416208341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6208100670 + 6208100671.

It is an arithmetic number, because the mean of its divisors is an integer number (6208100671).

Almost surely, 212416201341 is an apocalyptic number.

It is an amenable number.

12416201341 is a deficient number, since it is larger than the sum of its proper divisors (1).

12416201341 is an equidigital number, since it uses as much as digits as its factorization.

12416201341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 12416201341 its reverse (14310261421), we get a palindrome (26726462762).

The spelling of 12416201341 in words is "twelve billion, four hundred sixteen million, two hundred one thousand, three hundred forty-one".