Base | Representation |
---|---|
bin | 1011010010101111100001… |
… | …1101101100101010011111 |
3 | 1121222000110212200012021102 |
4 | 2310223320131230222133 |
5 | 3111413221222121002 |
6 | 42224041320423315 |
7 | 2421033342524345 |
oct | 264537035545237 |
9 | 47860425605242 |
10 | 12416624020127 |
11 | 3a57951616608 |
12 | 1486512317b3b |
13 | 6c0b6216cc12 |
14 | 30cd7994d995 |
15 | 167eb8ec4a02 |
hex | b4af876ca9f |
12416624020127 has 2 divisors, whose sum is σ = 12416624020128. Its totient is φ = 12416624020126.
The previous prime is 12416624020079. The next prime is 12416624020153. The reversal of 12416624020127 is 72102042661421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12416624020127 - 224 = 12416607242911 is a prime.
It is a super-2 number, since 2×124166240201272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12416624020027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6208312010063 + 6208312010064.
It is an arithmetic number, because the mean of its divisors is an integer number (6208312010064).
Almost surely, 212416624020127 is an apocalyptic number.
12416624020127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12416624020127 is an equidigital number, since it uses as much as digits as its factorization.
12416624020127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 38.
Adding to 12416624020127 its reverse (72102042661421), we get a palindrome (84518666681548).
The spelling of 12416624020127 in words is "twelve trillion, four hundred sixteen billion, six hundred twenty-four million, twenty thousand, one hundred twenty-seven".
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