12420134202103 has 2 divisors, whose sum is σ = 12420134202104. Its totient is φ = 12420134202102.

The previous prime is 12420134202031. The next prime is 12420134202107. The reversal of 12420134202103 is 30120243102421.

Together with previous prime (12420134202031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12420134202103 - 2¹⁷ = 12420134071031 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12420134202107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6210067101051 + 6210067101052.

It is an arithmetic number, because the mean of its divisors is an integer number (6210067101052).

Almost surely, 2^{12420134202103} is an apocalyptic number.

12420134202103 is a deficient number, since it is larger than the sum of its proper divisors (1).

12420134202103 is an equidigital number, since it uses as much as digits as its factorization.

12420134202103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12420134202103 its reverse (30120243102421), we get a palindrome (42540377304524).

The spelling of 12420134202103 in words is "twelve trillion, four hundred twenty billion, one hundred thirty-four million, two hundred two thousand, one hundred three".