Search a number
-
+
12421313431 is a prime number
BaseRepresentation
bin10111001000101111…
…00011001110010111
31012001122220002201121
423210113203032113
5200414324012211
65412315504411
7616545264532
oct134427431627
935048802647
1012421313431
1152a456469a
1224a7a58107
13122c529307
1485b96da19
154ca744271
hex2e45e3397

12421313431 has 2 divisors, whose sum is σ = 12421313432. Its totient is φ = 12421313430.

The previous prime is 12421313417. The next prime is 12421313459. The reversal of 12421313431 is 13431312421.

It is a weak prime.

It is an emirp because it is prime and its reverse (13431312421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12421313431 - 29 = 12421312919 is a prime.

It is a super-2 number, since 2×124213134312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12421313396 and 12421313405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12421313131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6210656715 + 6210656716.

It is an arithmetic number, because the mean of its divisors is an integer number (6210656716).

Almost surely, 212421313431 is an apocalyptic number.

12421313431 is a deficient number, since it is larger than the sum of its proper divisors (1).

12421313431 is an equidigital number, since it uses as much as digits as its factorization.

12421313431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 25.

Adding to 12421313431 its reverse (13431312421), we get a palindrome (25852625852).

The spelling of 12421313431 in words is "twelve billion, four hundred twenty-one million, three hundred thirteen thousand, four hundred thirty-one".