Base | Representation |
---|---|
bin | 10111001000110111… |
… | …10110100010011001 |
3 | 1012001202000101121121 |
4 | 23210123312202121 |
5 | 200420121103423 |
6 | 5412400005241 |
7 | 616561002325 |
oct | 134433664231 |
9 | 35052011547 |
10 | 12422441113 |
11 | 52a5164965 |
12 | 24a8300821 |
13 | 122c832694 |
14 | 85bb84985 |
15 | 4ca8b845d |
hex | 2e46f6899 |
12422441113 has 2 divisors, whose sum is σ = 12422441114. Its totient is φ = 12422441112.
The previous prime is 12422441111. The next prime is 12422441137. The reversal of 12422441113 is 31114422421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11576038464 + 846402649 = 107592^2 + 29093^2 .
It is an emirp because it is prime and its reverse (31114422421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12422441113 - 21 = 12422441111 is a prime.
Together with 12422441111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12422441111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6211220556 + 6211220557.
It is an arithmetic number, because the mean of its divisors is an integer number (6211220557).
Almost surely, 212422441113 is an apocalyptic number.
It is an amenable number.
12422441113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12422441113 is an equidigital number, since it uses as much as digits as its factorization.
12422441113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1536, while the sum is 25.
Adding to 12422441113 its reverse (31114422421), we get a palindrome (43536863534).
The spelling of 12422441113 in words is "twelve billion, four hundred twenty-two million, four hundred forty-one thousand, one hundred thirteen".
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