Base | Representation |
---|---|
bin | 11100001111110110000011… |
… | …110010100101110111100111 |
3 | 121021212200000211101221000202 |
4 | 130033312003302211313213 |
5 | 112240423004332130112 |
6 | 1120120213122101115 |
7 | 35111422543264451 |
oct | 3417660362456747 |
9 | 537780024357022 |
10 | 124234140114407 |
11 | 36648448354264 |
12 | 11b254aa1aa79b |
13 | 54422c95784ab |
14 | 2296d706c32d1 |
15 | e56935dae6c2 |
hex | 70fd83ca5de7 |
124234140114407 has 2 divisors, whose sum is σ = 124234140114408. Its totient is φ = 124234140114406.
The previous prime is 124234140114379. The next prime is 124234140114431. The reversal of 124234140114407 is 704411041432421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124234140114407 - 28 = 124234140114151 is a prime.
It is a super-2 number, since 2×1242341401144072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124234140114437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62117070057203 + 62117070057204.
It is an arithmetic number, because the mean of its divisors is an integer number (62117070057204).
Almost surely, 2124234140114407 is an apocalyptic number.
124234140114407 is a deficient number, since it is larger than the sum of its proper divisors (1).
124234140114407 is an equidigital number, since it uses as much as digits as its factorization.
124234140114407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 38.
Adding to 124234140114407 its reverse (704411041432421), we get a palindrome (828645181546828).
The spelling of 124234140114407 in words is "one hundred twenty-four trillion, two hundred thirty-four billion, one hundred forty million, one hundred fourteen thousand, four hundred seven".
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