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1242440113151 is a prime number
BaseRepresentation
bin10010000101000111001…
…100111001101111111111
311101202221210021020110002
4102011013030321233333
5130324004132110101
62350434043304515
7155522552466236
oct22050714715777
94352853236402
101242440113151
11439a09065276
1218096281b13b
139021405c0b3
14441c4bd7b1d
15224baa1dd6b
hex12147339bff

1242440113151 has 2 divisors, whose sum is σ = 1242440113152. Its totient is φ = 1242440113150.

The previous prime is 1242440113111. The next prime is 1242440113153. The reversal of 1242440113151 is 1513110442421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1242440113151 - 234 = 1225260243967 is a prime.

Together with 1242440113153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1242440113153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621220056575 + 621220056576.

It is an arithmetic number, because the mean of its divisors is an integer number (621220056576).

Almost surely, 21242440113151 is an apocalyptic number.

1242440113151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1242440113151 is an equidigital number, since it uses as much as digits as its factorization.

1242440113151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 1242440113151 its reverse (1513110442421), we get a palindrome (2755550555572).

The spelling of 1242440113151 in words is "one trillion, two hundred forty-two billion, four hundred forty million, one hundred thirteen thousand, one hundred fifty-one".