Base | Representation |
---|---|
bin | 10010000101101111001… |
… | …101101100110101100000 |
3 | 11101211200120102201000212 |
4 | 102011233031230311200 |
5 | 130331343010123130 |
6 | 2351024423433252 |
7 | 155545313436032 |
oct | 22055715546540 |
9 | 4354616381025 |
10 | 1243111411040 |
11 | 43a222a90314 |
12 | 180b0b5b5828 |
13 | 902c015c195 |
14 | 4424a01dc52 |
15 | 22509921e95 |
hex | 1216f36cd60 |
1243111411040 has 72 divisors (see below), whose sum is σ = 2958451195392. Its totient is φ = 493613849600.
The previous prime is 1243111411021. The next prime is 1243111411043. The reversal of 1243111411040 is 401141113421.
It is a junction number, because it is equal to n+sod(n) for n = 1243111410997 and 1243111411015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1243111411043) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2796065 + ... + 3210015.
It is an arithmetic number, because the mean of its divisors is an integer number (41089599936).
Almost surely, 21243111411040 is an apocalyptic number.
1243111411040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1243111411040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1479225597696).
1243111411040 is an abundant number, since it is smaller than the sum of its proper divisors (1715339784352).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1243111411040 is an equidigital number, since it uses as much as digits as its factorization.
1243111411040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 414240 (or 414095 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1243111411040 its reverse (401141113421), we get a palindrome (1644252524461).
It can be divided in two parts, 124311 and 1411040, that added together give a palindrome (1535351).
The spelling of 1243111411040 in words is "one trillion, two hundred forty-three billion, one hundred eleven million, four hundred eleven thousand, forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •