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12432015131573 is a prime number
BaseRepresentation
bin1011010011101000110111…
…0110001000001110110101
31122000111012111202200000002
42310322031312020032311
53112141231333202243
642235104445401045
72422116632025362
oct264721566101665
948014174680002
1012432015131573
113a6342a492424
1214894a8869185
136c2445a3785b
1430d9d9aa3469
151685ba2e3eb8
hexb4e8dd883b5

12432015131573 has 2 divisors, whose sum is σ = 12432015131574. Its totient is φ = 12432015131572.

The previous prime is 12432015131539. The next prime is 12432015131647. The reversal of 12432015131573 is 37513151023421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10952247498724 + 1479767632849 = 3309418^2 + 1216457^2 .

It is a cyclic number.

It is not a de Polignac number, because 12432015131573 - 28 = 12432015131317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12432015131533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6216007565786 + 6216007565787.

It is an arithmetic number, because the mean of its divisors is an integer number (6216007565787).

Almost surely, 212432015131573 is an apocalyptic number.

It is an amenable number.

12432015131573 is a deficient number, since it is larger than the sum of its proper divisors (1).

12432015131573 is an equidigital number, since it uses as much as digits as its factorization.

12432015131573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 38.

Adding to 12432015131573 its reverse (37513151023421), we get a palindrome (49945166154994).

The spelling of 12432015131573 in words is "twelve trillion, four hundred thirty-two billion, fifteen million, one hundred thirty-one thousand, five hundred seventy-three".