Base | Representation |
---|---|
bin | 111001111001100111… |
… | …1100000010000010101 |
3 | 102212221110200001210121 |
4 | 1303303033200100111 |
5 | 4014122020341203 |
6 | 133042045551541 |
7 | 11661155443525 |
oct | 1636317402025 |
9 | 385843601717 |
10 | 124340012053 |
11 | 48806771444 |
12 | 201212755b1 |
13 | b9573a5a3a |
14 | 60378c7685 |
15 | 337aee00bd |
hex | 1cf33e0415 |
124340012053 has 2 divisors, whose sum is σ = 124340012054. Its totient is φ = 124340012052.
The previous prime is 124340012047. The next prime is 124340012117. The reversal of 124340012053 is 350210043421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121833808209 + 2506203844 = 349047^2 + 50062^2 .
It is a cyclic number.
It is not a de Polignac number, because 124340012053 - 29 = 124340011541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124340012003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62170006026 + 62170006027.
It is an arithmetic number, because the mean of its divisors is an integer number (62170006027).
Almost surely, 2124340012053 is an apocalyptic number.
It is an amenable number.
124340012053 is a deficient number, since it is larger than the sum of its proper divisors (1).
124340012053 is an equidigital number, since it uses as much as digits as its factorization.
124340012053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 124340012053 its reverse (350210043421), we get a palindrome (474550055474).
The spelling of 124340012053 in words is "one hundred twenty-four billion, three hundred forty million, twelve thousand, fifty-three".
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