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12434101423 is a prime number
BaseRepresentation
bin10111001010010000…
…10101010010101111
31012002112221210112221
423211020111102233
5200431112221143
65413453540211
7620062055362
oct134510252257
935075853487
1012434101423
1153007a9487
1224b01a4667
131232085b83
1485d53c0d9
154cb91d2ed
hex2e52154af

12434101423 has 2 divisors, whose sum is σ = 12434101424. Its totient is φ = 12434101422.

The previous prime is 12434101417. The next prime is 12434101499. The reversal of 12434101423 is 32410143421.

12434101423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12434101423 - 221 = 12432004271 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12434101723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6217050711 + 6217050712.

It is an arithmetic number, because the mean of its divisors is an integer number (6217050712).

Almost surely, 212434101423 is an apocalyptic number.

12434101423 is a deficient number, since it is larger than the sum of its proper divisors (1).

12434101423 is an equidigital number, since it uses as much as digits as its factorization.

12434101423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12434101423 its reverse (32410143421), we get a palindrome (44844244844).

The spelling of 12434101423 in words is "twelve billion, four hundred thirty-four million, one hundred one thousand, four hundred twenty-three".