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124342201981 is a prime number
BaseRepresentation
bin111001111001101011…
…1110110111001111101
3102212221121210022211001
41303303113312321331
54014123100430411
6133042204530301
711661213164254
oct1636327667175
9385847708731
10124342201981
1148807a277a8
1220121b50991
13b95799175a
146037cd779b
15337b2c3dc1
hex1cf35f6e7d

124342201981 has 2 divisors, whose sum is σ = 124342201982. Its totient is φ = 124342201980.

The previous prime is 124342201979. The next prime is 124342202003. The reversal of 124342201981 is 189102243421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124189284025 + 152917956 = 352405^2 + 12366^2 .

It is a cyclic number.

It is not a de Polignac number, because 124342201981 - 21 = 124342201979 is a prime.

It is a super-2 number, since 2×1243422019812 (a number of 23 digits) contains 22 as substring.

Together with 124342201979, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 124342201981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124342201931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62171100990 + 62171100991.

It is an arithmetic number, because the mean of its divisors is an integer number (62171100991).

Almost surely, 2124342201981 is an apocalyptic number.

It is an amenable number.

124342201981 is a deficient number, since it is larger than the sum of its proper divisors (1).

124342201981 is an equidigital number, since it uses as much as digits as its factorization.

124342201981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 37.

The spelling of 124342201981 in words is "one hundred twenty-four billion, three hundred forty-two million, two hundred one thousand, nine hundred eighty-one".