Base | Representation |
---|---|
bin | 10111001010011000… |
… | …10011001001001001 |
3 | 1012002121220121211221 |
4 | 23211030103021021 |
5 | 200431344004233 |
6 | 5413532122041 |
7 | 620103645646 |
oct | 134514231111 |
9 | 35077817757 |
10 | 12435141193 |
11 | 53013496a2 |
12 | 24b0606321 |
13 | 123235b217 |
14 | 85d72cdcd |
15 | 4cba7642d |
hex | 2e5313249 |
12435141193 has 2 divisors, whose sum is σ = 12435141194. Its totient is φ = 12435141192.
The previous prime is 12435141179. The next prime is 12435141227. The reversal of 12435141193 is 39114153421.
It is an a-pointer prime, because the next prime (12435141227) can be obtained adding 12435141193 to its sum of digits (34).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9894678784 + 2540462409 = 99472^2 + 50403^2 .
It is a cyclic number.
It is not a de Polignac number, because 12435141193 - 29 = 12435140681 is a prime.
It is not a weakly prime, because it can be changed into another prime (12435141293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6217570596 + 6217570597.
It is an arithmetic number, because the mean of its divisors is an integer number (6217570597).
Almost surely, 212435141193 is an apocalyptic number.
It is an amenable number.
12435141193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12435141193 is an equidigital number, since it uses as much as digits as its factorization.
12435141193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12960, while the sum is 34.
The spelling of 12435141193 in words is "twelve billion, four hundred thirty-five million, one hundred forty-one thousand, one hundred ninety-three".
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