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1243843604819 is a prime number
BaseRepresentation
bin10010000110011010110…
…110110011000101010011
311101220120121012000001222
4102012122312303011103
5130334342430323234
62351225221115255
7155602414123544
oct22063266630523
94356517160058
101243843604819
1143a569319342
12181094858b2b
13903a8a60c3a
14442b93784cb
152254dd5342e
hex1219adb3153

1243843604819 has 2 divisors, whose sum is σ = 1243843604820. Its totient is φ = 1243843604818.

The previous prime is 1243843604797. The next prime is 1243843604821. The reversal of 1243843604819 is 9184063483421.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1243843604819 is a prime.

It is a super-2 number, since 2×12438436048192 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1243843604821, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1243843609819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621921802409 + 621921802410.

It is an arithmetic number, because the mean of its divisors is an integer number (621921802410).

Almost surely, 21243843604819 is an apocalyptic number.

1243843604819 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243843604819 is an equidigital number, since it uses as much as digits as its factorization.

1243843604819 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3981312, while the sum is 53.

The spelling of 1243843604819 in words is "one trillion, two hundred forty-three billion, eight hundred forty-three million, six hundred four thousand, eight hundred nineteen".