Base | Representation |
---|---|
bin | 1011010100000111000100… |
… | …1111100110101100110111 |
3 | 1122001021010201022002200012 |
4 | 2311001301033212230313 |
5 | 3112304334023032203 |
6 | 42242525320410435 |
7 | 2422524620355245 |
oct | 265016117465467 |
9 | 48037121262605 |
10 | 12440125205303 |
11 | 3a669114018a4 |
12 | 148ab90916a1b |
13 | 6c313900a753 |
14 | 310168c21795 |
15 | 1688e22d3bd8 |
hex | b50713e6b37 |
12440125205303 has 2 divisors, whose sum is σ = 12440125205304. Its totient is φ = 12440125205302.
The previous prime is 12440125205267. The next prime is 12440125205371. The reversal of 12440125205303 is 30350252104421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12440125205303 - 230 = 12439051463479 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12440125205303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12440125205203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220062602651 + 6220062602652.
It is an arithmetic number, because the mean of its divisors is an integer number (6220062602652).
Almost surely, 212440125205303 is an apocalyptic number.
12440125205303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12440125205303 is an equidigital number, since it uses as much as digits as its factorization.
12440125205303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 12440125205303 its reverse (30350252104421), we get a palindrome (42790377309724).
The spelling of 12440125205303 in words is "twelve trillion, four hundred forty billion, one hundred twenty-five million, two hundred five thousand, three hundred three".
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