Base | Representation |
---|---|
bin | 1011010100000111011110… |
… | …1110101000001110010111 |
3 | 1122001021102022000111201200 |
4 | 2311001313232220032113 |
5 | 3112310044401020203 |
6 | 42242544204323543 |
7 | 2422530411203613 |
oct | 265016756501627 |
9 | 48037368014650 |
10 | 12440234001303 |
11 | 3a66967860949 |
12 | 148b0012435b3 |
13 | 6c3155710a94 |
14 | 310179462343 |
15 | 1688ebb249a3 |
hex | b5077ba8397 |
12440234001303 has 48 divisors (see below), whose sum is σ = 18521848800000. Its totient is φ = 8042161780224.
The previous prime is 12440234001269. The next prime is 12440234001311. The reversal of 12440234001303 is 30310043204421.
12440234001303 is a `hidden beast` number, since 1 + 244 + 0 + 2 + 3 + 400 + 13 + 0 + 3 = 666.
It is not a de Polignac number, because 12440234001303 - 217 = 12440233870231 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12440234001343) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 101783673 + ... + 101905821.
It is an arithmetic number, because the mean of its divisors is an integer number (385871850000).
Almost surely, 212440234001303 is an apocalyptic number.
12440234001303 is a deficient number, since it is larger than the sum of its proper divisors (6081614798697).
12440234001303 is a wasteful number, since it uses less digits than its factorization.
12440234001303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124696 (or 124693 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 12440234001303 its reverse (30310043204421), we get a palindrome (42750277205724).
The spelling of 12440234001303 in words is "twelve trillion, four hundred forty billion, two hundred thirty-four million, one thousand, three hundred three".
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