Base | Representation |
---|---|
bin | 10010000110100101110… |
… | …100000000001001100011 |
3 | 11101221001102001211212011 |
4 | 102012211310000021203 |
5 | 130340232004440113 |
6 | 2351255345013351 |
7 | 155610105415603 |
oct | 22064564001143 |
9 | 4357042054764 |
10 | 1244027421283 |
11 | 43a653058379 |
12 | 181126324257 |
13 | 90407b6cc8a |
14 | 442d5946c03 |
15 | 2256006263d |
hex | 121a5d00263 |
1244027421283 has 2 divisors, whose sum is σ = 1244027421284. Its totient is φ = 1244027421282.
The previous prime is 1244027421277. The next prime is 1244027421289. The reversal of 1244027421283 is 3821247204421.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (1244027421277) and next prime (1244027421289).
It is a cyclic number.
It is not a de Polignac number, because 1244027421283 - 225 = 1243993866851 is a prime.
It is a super-2 number, since 2×12440274212832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1244027421289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622013710641 + 622013710642.
It is an arithmetic number, because the mean of its divisors is an integer number (622013710642).
Almost surely, 21244027421283 is an apocalyptic number.
1244027421283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1244027421283 is an equidigital number, since it uses as much as digits as its factorization.
1244027421283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172032, while the sum is 40.
The spelling of 1244027421283 in words is "one trillion, two hundred forty-four billion, twenty-seven million, four hundred twenty-one thousand, two hundred eighty-three".
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