12440314130 has 32 divisors (see below), whose sum is σ = 22641208128. Its totient is φ = 4921134400.

The previous prime is 12440314123. The next prime is 12440314141. The reversal of 12440314130 is 3141304421.

It is a super-2 number, since 2×12440314130² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12440314096 and 12440314105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 367625 + ... + 400035.

It is an arithmetic number, because the mean of its divisors is an integer number (707537754).

Almost surely, 2^12440314130 is an apocalyptic number.

12440314130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12440314130 is a deficient number, since it is larger than the sum of its proper divisors (10200893998).

12440314130 is a wasteful number, since it uses less digits than its factorization.

12440314130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32842.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12440314130 its reverse (3141304421), we get a palindrome (15581618551).

The spelling of 12440314130 in words is "twelve billion, four hundred forty million, three hundred fourteen thousand, one hundred thirty".