Base | Representation |
---|---|
bin | 1011010100001011100111… |
… | …0110110100000101101111 |
3 | 1122001101021121122000001102 |
4 | 2311002321312310011233 |
5 | 3112314332410141221 |
6 | 42243250235433315 |
7 | 2422600042253456 |
oct | 265027166640557 |
9 | 48041247560042 |
10 | 12441343443311 |
11 | 3a67387035072 |
12 | 148b2708b583b |
13 | 6c32a1519343 |
14 | 31024293bb9d |
15 | 16896422330b |
hex | b50b9db416f |
12441343443311 has 2 divisors, whose sum is σ = 12441343443312. Its totient is φ = 12441343443310.
The previous prime is 12441343443289. The next prime is 12441343443359. The reversal of 12441343443311 is 11334434314421.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12441343443311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12441343443811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220671721655 + 6220671721656.
It is an arithmetic number, because the mean of its divisors is an integer number (6220671721656).
Almost surely, 212441343443311 is an apocalyptic number.
12441343443311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12441343443311 is an equidigital number, since it uses as much as digits as its factorization.
12441343443311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 165888, while the sum is 38.
Adding to 12441343443311 its reverse (11334434314421), we get a palindrome (23775777757732).
The spelling of 12441343443311 in words is "twelve trillion, four hundred forty-one billion, three hundred forty-three million, four hundred forty-three thousand, three hundred eleven".
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