Base | Representation |
---|---|
bin | 10111001110100000… |
… | …01010000011100101 |
3 | 1012012000221202012022 |
4 | 23213100022003211 |
5 | 201014221110411 |
6 | 5421205032525 |
7 | 621003521564 |
oct | 134720120345 |
9 | 35160852168 |
10 | 12469706981 |
11 | 5319908466 |
12 | 25000b5745 |
13 | 1239571454 |
14 | 864169bdb |
15 | 4ceb02edb |
hex | 2e740a0e5 |
12469706981 has 2 divisors, whose sum is σ = 12469706982. Its totient is φ = 12469706980.
The previous prime is 12469706927. The next prime is 12469706987. The reversal of 12469706981 is 18960796421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9136492225 + 3333214756 = 95585^2 + 57734^2 .
It is a cyclic number.
It is not a de Polignac number, because 12469706981 - 230 = 11395965157 is a prime.
It is a super-2 number, since 2×124697069812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12469706987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6234853490 + 6234853491.
It is an arithmetic number, because the mean of its divisors is an integer number (6234853491).
Almost surely, 212469706981 is an apocalyptic number.
It is an amenable number.
12469706981 is a deficient number, since it is larger than the sum of its proper divisors (1).
12469706981 is an equidigital number, since it uses as much as digits as its factorization.
12469706981 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 53.
The spelling of 12469706981 in words is "twelve billion, four hundred sixty-nine million, seven hundred six thousand, nine hundred eighty-one".
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