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12480477161917 is a prime number
BaseRepresentation
bin1011010110011101011001…
…1010000110100110111101
31122012010021220121212212211
42311213112122012212331
53113440004123140132
642313241351100421
72425453600342522
oct265472632064675
948163256555784
1012480477161917
113a81a38aa1076
121496972671711
136c6b99c7c95b
143120b6049149
151699a4b3e147
hexb59d66869bd

12480477161917 has 2 divisors, whose sum is σ = 12480477161918. Its totient is φ = 12480477161916.

The previous prime is 12480477161891. The next prime is 12480477161923. The reversal of 12480477161917 is 71916177408421.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11625331244836 + 855145917081 = 3409594^2 + 924741^2 .

It is an emirp because it is prime and its reverse (71916177408421) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12480477161917 is a prime.

It is a super-2 number, since 2×124804771619172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12450477161917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6240238580958 + 6240238580959.

It is an arithmetic number, because the mean of its divisors is an integer number (6240238580959).

Almost surely, 212480477161917 is an apocalyptic number.

It is an amenable number.

12480477161917 is a deficient number, since it is larger than the sum of its proper divisors (1).

12480477161917 is an equidigital number, since it uses as much as digits as its factorization.

12480477161917 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4741632, while the sum is 58.

The spelling of 12480477161917 in words is "twelve trillion, four hundred eighty billion, four hundred seventy-seven million, one hundred sixty-one thousand, nine hundred seventeen".