Base | Representation |
---|---|
bin | 1011010111101010000011… |
… | …1101001000111101101101 |
3 | 1122021002102000212012201112 |
4 | 2311322200331020331231 |
5 | 3114304130113312141 |
6 | 42330523330121405 |
7 | 2430112542033005 |
oct | 265724075107555 |
9 | 48232360765645 |
10 | 12501055213421 |
11 | 3a8a738847805 |
12 | 149a956120265 |
13 | 6c8ac9339ba8 |
14 | 3130a9003005 |
15 | 16a2ab4de7eb |
hex | b5ea0f48f6d |
12501055213421 has 2 divisors, whose sum is σ = 12501055213422. Its totient is φ = 12501055213420.
The previous prime is 12501055213417. The next prime is 12501055213433. The reversal of 12501055213421 is 12431255010521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9211747027396 + 3289308186025 = 3035086^2 + 1813645^2 .
It is a cyclic number.
It is not a de Polignac number, because 12501055213421 - 22 = 12501055213417 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12501055203421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250527606710 + 6250527606711.
It is an arithmetic number, because the mean of its divisors is an integer number (6250527606711).
Almost surely, 212501055213421 is an apocalyptic number.
It is an amenable number.
12501055213421 is a deficient number, since it is larger than the sum of its proper divisors (1).
12501055213421 is an equidigital number, since it uses as much as digits as its factorization.
12501055213421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 12501055213421 in words is "twelve trillion, five hundred one billion, fifty-five million, two hundred thirteen thousand, four hundred twenty-one".
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