Search a number
-
+
12501247138013 is a prime number
BaseRepresentation
bin1011010111101010110001…
…1001010001100011011101
31122021002220101222222202202
42311322230121101203131
53114310023231404023
642330554343501245
72430120362254634
oct265725431214335
948232811888682
1012501247138013
113a8a827114577
12149a9aa457825
136c8b2a02763a
143130c66c251b
1516a2bd2a1128
hexb5eac6518dd

12501247138013 has 2 divisors, whose sum is σ = 12501247138014. Its totient is φ = 12501247138012.

The previous prime is 12501247138007. The next prime is 12501247138073. The reversal of 12501247138013 is 31083174210521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11066287519609 + 1434959618404 = 3326603^2 + 1197898^2 .

It is a cyclic number.

It is not a de Polignac number, because 12501247138013 - 24 = 12501247137997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12501247138073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250623569006 + 6250623569007.

It is an arithmetic number, because the mean of its divisors is an integer number (6250623569007).

Almost surely, 212501247138013 is an apocalyptic number.

It is an amenable number.

12501247138013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12501247138013 is an equidigital number, since it uses as much as digits as its factorization.

12501247138013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 12501247138013 in words is "twelve trillion, five hundred one billion, two hundred forty-seven million, one hundred thirty-eight thousand, thirteen".