Base | Representation |
---|---|
bin | 1011010111101010110001… |
… | …1001010001100011011101 |
3 | 1122021002220101222222202202 |
4 | 2311322230121101203131 |
5 | 3114310023231404023 |
6 | 42330554343501245 |
7 | 2430120362254634 |
oct | 265725431214335 |
9 | 48232811888682 |
10 | 12501247138013 |
11 | 3a8a827114577 |
12 | 149a9aa457825 |
13 | 6c8b2a02763a |
14 | 3130c66c251b |
15 | 16a2bd2a1128 |
hex | b5eac6518dd |
12501247138013 has 2 divisors, whose sum is σ = 12501247138014. Its totient is φ = 12501247138012.
The previous prime is 12501247138007. The next prime is 12501247138073. The reversal of 12501247138013 is 31083174210521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11066287519609 + 1434959618404 = 3326603^2 + 1197898^2 .
It is a cyclic number.
It is not a de Polignac number, because 12501247138013 - 24 = 12501247137997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12501247138073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250623569006 + 6250623569007.
It is an arithmetic number, because the mean of its divisors is an integer number (6250623569007).
Almost surely, 212501247138013 is an apocalyptic number.
It is an amenable number.
12501247138013 is a deficient number, since it is larger than the sum of its proper divisors (1).
12501247138013 is an equidigital number, since it uses as much as digits as its factorization.
12501247138013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 38.
The spelling of 12501247138013 in words is "twelve trillion, five hundred one billion, two hundred forty-seven million, one hundred thirty-eight thousand, thirteen".
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