1250144341142 has 16 divisors (see below), whose sum is σ = 1907134156800. Its totient is φ = 614434448040.

The previous prime is 1250144341093. The next prime is 1250144341247. The reversal of 1250144341142 is 2411434410521.

It is a junction number, because it is equal to n+sod(n) for n = 1250144341099 and 1250144341108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1342667 + ... + 2074377.

It is an arithmetic number, because the mean of its divisors is an integer number (119195884800).

Almost surely, 2^{1250144341142} is an apocalyptic number.

1250144341142 is a deficient number, since it is larger than the sum of its proper divisors (656989815658).

1250144341142 is a wasteful number, since it uses less digits than its factorization.

1250144341142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 746251.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 1250144341142 its reverse (2411434410521), we get a palindrome (3661578751663).

The spelling of 1250144341142 in words is "one trillion, two hundred fifty billion, one hundred forty-four million, three hundred forty-one thousand, one hundred forty-two".