Base | Representation |
---|---|
bin | 1011010111101111001010… |
… | …0110011101100101111101 |
3 | 1122021012221111100121002112 |
4 | 2311323302212131211331 |
5 | 3114314431300002232 |
6 | 42331311301303405 |
7 | 2430161514031550 |
oct | 265736246354575 |
9 | 48235844317075 |
10 | 12502425000317 |
11 | 3a90280a7a99a |
12 | 149b078a04b65 |
13 | 6c8c8706a695 |
14 | 313198ccc697 |
15 | 16a33b8b74b2 |
hex | b5ef299d97d |
12502425000317 has 16 divisors (see below), whose sum is σ = 14361044064000. Its totient is φ = 10661951203200.
The previous prime is 12502425000283. The next prime is 12502425000323. The reversal of 12502425000317 is 71300052420521.
It is a cyclic number.
It is not a de Polignac number, because 12502425000317 - 212 = 12502424996221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12502425000347) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27356159 + ... + 27809427.
It is an arithmetic number, because the mean of its divisors is an integer number (897565254000).
Almost surely, 212502425000317 is an apocalyptic number.
It is an amenable number.
12502425000317 is a deficient number, since it is larger than the sum of its proper divisors (1858619063683).
12502425000317 is a wasteful number, since it uses less digits than its factorization.
12502425000317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 473276.
The product of its (nonzero) digits is 16800, while the sum is 32.
Adding to 12502425000317 its reverse (71300052420521), we get a palindrome (83802477420838).
The spelling of 12502425000317 in words is "twelve trillion, five hundred two billion, four hundred twenty-five million, three hundred seventeen", and thus it is an aban number.
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