Base | Representation |
---|---|
bin | 111010001110011110… |
… | …1111100010100000111 |
3 | 102221202020220202100011 |
4 | 1310130331330110013 |
5 | 4022040223121323 |
6 | 133235334131051 |
7 | 12014415620665 |
oct | 1643475742407 |
9 | 387666822304 |
10 | 125040051463 |
11 | 49035938408 |
12 | 202977b0a87 |
13 | ba3942a042 |
14 | 60a2871c35 |
15 | 33bc6be20d |
hex | 1d1cf7c507 |
125040051463 has 2 divisors, whose sum is σ = 125040051464. Its totient is φ = 125040051462.
The previous prime is 125040051443. The next prime is 125040051467. The reversal of 125040051463 is 364150040521.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125040051463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125040051467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62520025731 + 62520025732.
It is an arithmetic number, because the mean of its divisors is an integer number (62520025732).
Almost surely, 2125040051463 is an apocalyptic number.
125040051463 is a deficient number, since it is larger than the sum of its proper divisors (1).
125040051463 is an equidigital number, since it uses as much as digits as its factorization.
125040051463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 125040051463 its reverse (364150040521), we get a palindrome (489190091984).
The spelling of 125040051463 in words is "one hundred twenty-five billion, forty million, fifty-one thousand, four hundred sixty-three".
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