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12504022224539 is a prime number
BaseRepresentation
bin1011010111110101000111…
…0011011000111010011011
31122021101001210210222211012
42311331101303120322123
53114331214142141124
642332133555324135
72430246220151126
oct265752163307233
948241053728735
1012504022224539
113a90a2062610a
12149b4438b064b
136c917cc40b81
143132ab09d3bd
1516a3d1c18e0e
hexb5f51cd8e9b

12504022224539 has 2 divisors, whose sum is σ = 12504022224540. Its totient is φ = 12504022224538.

The previous prime is 12504022224523. The next prime is 12504022224541. The reversal of 12504022224539 is 93542222040521.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (93542222040521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12504022224539 - 24 = 12504022224523 is a prime.

Together with 12504022224541, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12504022224496 and 12504022224505.

It is not a weakly prime, because it can be changed into another prime (12504022224569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6252011112269 + 6252011112270.

It is an arithmetic number, because the mean of its divisors is an integer number (6252011112270).

Almost surely, 212504022224539 is an apocalyptic number.

12504022224539 is a deficient number, since it is larger than the sum of its proper divisors (1).

12504022224539 is an equidigital number, since it uses as much as digits as its factorization.

12504022224539 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 41.

The spelling of 12504022224539 in words is "twelve trillion, five hundred four billion, twenty-two million, two hundred twenty-four thousand, five hundred thirty-nine".