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12504085199399 is a prime number
BaseRepresentation
bin1011010111110101010110…
…0011100111101000100111
31122021101020012022110002102
42311331111203213220213
53114331331302340044
642332144125202315
72430250613345243
oct265752543475047
948241205273072
1012504085199399
113a90a53129052
12149b460a0039b
136c918ccbcbc1
143132b55b3423
1516a3d750824e
hexb5f558e7a27

12504085199399 has 2 divisors, whose sum is σ = 12504085199400. Its totient is φ = 12504085199398.

The previous prime is 12504085199363. The next prime is 12504085199407. The reversal of 12504085199399 is 99399158040521.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12504085199399 is a prime.

It is a super-2 number, since 2×125040851993992 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12504085169399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6252042599699 + 6252042599700.

It is an arithmetic number, because the mean of its divisors is an integer number (6252042599700).

Almost surely, 212504085199399 is an apocalyptic number.

12504085199399 is a deficient number, since it is larger than the sum of its proper divisors (1).

12504085199399 is an equidigital number, since it uses as much as digits as its factorization.

12504085199399 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31492800, while the sum is 65.

The spelling of 12504085199399 in words is "twelve trillion, five hundred four billion, eighty-five million, one hundred ninety-nine thousand, three hundred ninety-nine".