125041200437 has 2 divisors, whose sum is σ = 125041200438. Its totient is φ = 125041200436.

The previous prime is 125041200407. The next prime is 125041200439. The reversal of 125041200437 is 734002140521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124034978596 + 1006221841 = 352186^2 + 31721^2 .

It is a cyclic number.

It is not a de Polignac number, because 125041200437 - 2¹⁸ = 125040938293 is a prime.

Together with 125041200439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125041200439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62520600218 + 62520600219.

It is an arithmetic number, because the mean of its divisors is an integer number (62520600219).

Almost surely, 2^125041200437 is an apocalyptic number.

It is an amenable number.

125041200437 is a deficient number, since it is larger than the sum of its proper divisors (1).

125041200437 is an equidigital number, since it uses as much as digits as its factorization.

125041200437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 29.

Adding to 125041200437 its reverse (734002140521), we get a palindrome (859043340958).

The spelling of 125041200437 in words is "one hundred twenty-five billion, forty-one million, two hundred thousand, four hundred thirty-seven".