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125104601537 is a prime number
BaseRepresentation
bin111010010000011010…
…0001011100111000001
3102221220202101020101122
41310200310023213001
54022203234222122
6133250001442025
712016131365426
oct1644064134701
9387822336348
10125104601537
1149069316883
12202b5340315
13ba4990b056
1460ab275d4d
1533c31c0142
hex1d20d0b9c1

125104601537 has 2 divisors, whose sum is σ = 125104601538. Its totient is φ = 125104601536.

The previous prime is 125104601459. The next prime is 125104601683. The reversal of 125104601537 is 735106401521.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116751372721 + 8353228816 = 341689^2 + 91396^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125104601537 is a prime.

It is a super-2 number, since 2×1251046015372 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125104601497 and 125104601506.

It is not a weakly prime, because it can be changed into another prime (125104601437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62552300768 + 62552300769.

It is an arithmetic number, because the mean of its divisors is an integer number (62552300769).

Almost surely, 2125104601537 is an apocalyptic number.

It is an amenable number.

125104601537 is a deficient number, since it is larger than the sum of its proper divisors (1).

125104601537 is an equidigital number, since it uses as much as digits as its factorization.

125104601537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 35.

The spelling of 125104601537 in words is "one hundred twenty-five billion, one hundred four million, six hundred one thousand, five hundred thirty-seven".