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125104601437 is a prime number
BaseRepresentation
bin111010010000011010…
…0001011100101011101
3102221220202101020020221
41310200310023211131
54022203234221222
6133250001441341
712016131365224
oct1644064134535
9387822336227
10125104601437
11490693167a2
12202b5340251
13ba4990acaa
1460ab275cbb
1533c31c00c7
hex1d20d0b95d

125104601437 has 2 divisors, whose sum is σ = 125104601438. Its totient is φ = 125104601436.

The previous prime is 125104601411. The next prime is 125104601441. The reversal of 125104601437 is 734106401521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123356190841 + 1748410596 = 351221^2 + 41814^2 .

It is a cyclic number.

It is not a de Polignac number, because 125104601437 - 27 = 125104601309 is a prime.

It is a super-2 number, since 2×1251046014372 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125104601537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62552300718 + 62552300719.

It is an arithmetic number, because the mean of its divisors is an integer number (62552300719).

Almost surely, 2125104601437 is an apocalyptic number.

It is an amenable number.

125104601437 is a deficient number, since it is larger than the sum of its proper divisors (1).

125104601437 is an equidigital number, since it uses as much as digits as its factorization.

125104601437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 34.

The spelling of 125104601437 in words is "one hundred twenty-five billion, one hundred four million, six hundred one thousand, four hundred thirty-seven".