Base | Representation |
---|---|
bin | 111010010000011010… |
… | …1110010100110110011 |
3 | 102221220210011200002121 |
4 | 1310200311302212303 |
5 | 4022203341222121 |
6 | 133250014455111 |
7 | 12016135103404 |
oct | 1644065624663 |
9 | 387823150077 |
10 | 125105023411 |
11 | 49069584835 |
12 | 202b5504497 |
13 | ba49a28094 |
14 | 60ab3459ab |
15 | 33c3255141 |
hex | 1d20d729b3 |
125105023411 has 2 divisors, whose sum is σ = 125105023412. Its totient is φ = 125105023410.
The previous prime is 125105023409. The next prime is 125105023429. The reversal of 125105023411 is 114320501521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125105023411 - 21 = 125105023409 is a prime.
Together with 125105023409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (125105023441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62552511705 + 62552511706.
It is an arithmetic number, because the mean of its divisors is an integer number (62552511706).
Almost surely, 2125105023411 is an apocalyptic number.
125105023411 is a deficient number, since it is larger than the sum of its proper divisors (1).
125105023411 is an equidigital number, since it uses as much as digits as its factorization.
125105023411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 125105023411 its reverse (114320501521), we get a palindrome (239425524932).
The spelling of 125105023411 in words is "one hundred twenty-five billion, one hundred five million, twenty-three thousand, four hundred eleven".
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