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125130100993 is a prime number
BaseRepresentation
bin111010010001001010…
…1011101000100000001
3102221222112100202001221
41310202111131010001
54022231301212433
6133252312155041
712016561211032
oct1644225350401
9387875322057
10125130100993
1149081752a07
1220301998a81
13ba51c986a1
1460b07d2a89
1533c555a72d
hex1d2255d101

125130100993 has 2 divisors, whose sum is σ = 125130100994. Its totient is φ = 125130100992.

The previous prime is 125130100973. The next prime is 125130101027. The reversal of 125130100993 is 399001031521.

It is an a-pointer prime, because the next prime (125130101027) can be obtained adding 125130100993 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73640591424 + 51489509569 = 271368^2 + 226913^2 .

It is a cyclic number.

It is not a de Polignac number, because 125130100993 - 29 = 125130100481 is a prime.

It is not a weakly prime, because it can be changed into another prime (125130100973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62565050496 + 62565050497.

It is an arithmetic number, because the mean of its divisors is an integer number (62565050497).

Almost surely, 2125130100993 is an apocalyptic number.

It is an amenable number.

125130100993 is a deficient number, since it is larger than the sum of its proper divisors (1).

125130100993 is an equidigital number, since it uses as much as digits as its factorization.

125130100993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7290, while the sum is 34.

The spelling of 125130100993 in words is "one hundred twenty-five billion, one hundred thirty million, one hundred thousand, nine hundred ninety-three".