Base | Representation |
---|---|
bin | 1011011000010111100010… |
… | …1001000010010100010001 |
3 | 1122022020220212101110110222 |
4 | 2312011320221002110101 |
5 | 3120004131010202221 |
6 | 42340303005402425 |
7 | 2431024224655151 |
oct | 266057051022421 |
9 | 48266825343428 |
10 | 12513263756561 |
11 | 3a94933196987 |
12 | 14a11a2869415 |
13 | 6c9cc375a409 |
14 | 3139065c8761 |
15 | 16a7732059ab |
hex | b6178a42511 |
12513263756561 has 2 divisors, whose sum is σ = 12513263756562. Its totient is φ = 12513263756560.
The previous prime is 12513263756423. The next prime is 12513263756593. The reversal of 12513263756561 is 16565736231521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7030028016400 + 5483235740161 = 2651420^2 + 2341631^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12513263756561 is a prime.
It is not a weakly prime, because it can be changed into another prime (12513263756261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256631878280 + 6256631878281.
It is an arithmetic number, because the mean of its divisors is an integer number (6256631878281).
Almost surely, 212513263756561 is an apocalyptic number.
It is an amenable number.
12513263756561 is a deficient number, since it is larger than the sum of its proper divisors (1).
12513263756561 is an equidigital number, since it uses as much as digits as its factorization.
12513263756561 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6804000, while the sum is 53.
The spelling of 12513263756561 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty-six thousand, five hundred sixty-one".
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