Base | Representation |
---|---|
bin | 1011011000010111100010… |
… | …1001000010010010000111 |
3 | 1122022020220212101110021212 |
4 | 2312011320221002102013 |
5 | 3120004131010201143 |
6 | 42340303005402035 |
7 | 2431024224654563 |
oct | 266057051022207 |
9 | 48266825343255 |
10 | 12513263756423 |
11 | 3a94933196871 |
12 | 14a11a286931b |
13 | 6c9cc375a331 |
14 | 3139065c86a3 |
15 | 16a773205918 |
hex | b6178a42487 |
12513263756423 has 2 divisors, whose sum is σ = 12513263756424. Its totient is φ = 12513263756422.
The previous prime is 12513263756419. The next prime is 12513263756561. The reversal of 12513263756423 is 32465736231521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12513263756423 - 22 = 12513263756419 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12513263716423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256631878211 + 6256631878212.
It is an arithmetic number, because the mean of its divisors is an integer number (6256631878212).
Almost surely, 212513263756423 is an apocalyptic number.
12513263756423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12513263756423 is an equidigital number, since it uses as much as digits as its factorization.
12513263756423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5443200, while the sum is 50.
Adding to 12513263756423 its reverse (32465736231521), we get a palindrome (44978999987944).
The spelling of 12513263756423 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty-six thousand, four hundred twenty-three".
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