Base | Representation |
---|---|
bin | 111010010001101111… |
… | …1000101100110110101 |
3 | 102222000212200102020022 |
4 | 1310203133011212311 |
5 | 4022301221403243 |
6 | 133254242014525 |
7 | 12020214243545 |
oct | 1644337054665 |
9 | 388025612208 |
10 | 125149403573 |
11 | 49091637257 |
12 | 20308347445 |
13 | ba55c9652c |
14 | 60b31b9325 |
15 | 33c70beb68 |
hex | 1d237c59b5 |
125149403573 has 2 divisors, whose sum is σ = 125149403574. Its totient is φ = 125149403572.
The previous prime is 125149403521. The next prime is 125149403593. The reversal of 125149403573 is 375304941521.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106694996164 + 18454407409 = 326642^2 + 135847^2 .
It is a cyclic number.
It is not a de Polignac number, because 125149403573 - 210 = 125149402549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125149403503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62574701786 + 62574701787.
It is an arithmetic number, because the mean of its divisors is an integer number (62574701787).
Almost surely, 2125149403573 is an apocalyptic number.
It is an amenable number.
125149403573 is a deficient number, since it is larger than the sum of its proper divisors (1).
125149403573 is an equidigital number, since it uses as much as digits as its factorization.
125149403573 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 453600, while the sum is 44.
The spelling of 125149403573 in words is "one hundred twenty-five billion, one hundred forty-nine million, four hundred three thousand, five hundred seventy-three".
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