Base | Representation |
---|---|
bin | 1011011000110100110101… |
… | …0001010111100010101110 |
3 | 1122100000012210201011220211 |
4 | 2312031031101113202232 |
5 | 3120121231233110400 |
6 | 42344043110133034 |
7 | 2431423114335136 |
oct | 266151521274256 |
9 | 48300183634824 |
10 | 12521126066350 |
11 | 3a981a826a670 |
12 | 14a281795117a |
13 | 6ca9775c1625 |
14 | 31405088dac6 |
15 | 16aa835a3dba |
hex | b634d4578ae |
12521126066350 has 48 divisors (see below), whose sum is σ = 25422413749776. Its totient is φ = 4550285376000.
The previous prime is 12521126066321. The next prime is 12521126066369. The reversal of 12521126066350 is 5366062112521.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6249291 + ... + 8005990.
It is an arithmetic number, because the mean of its divisors is an integer number (529633619787).
Almost surely, 212521126066350 is an apocalyptic number.
12521126066350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12521126066350 is an abundant number, since it is smaller than the sum of its proper divisors (12901287683426).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12521126066350 is a wasteful number, since it uses less digits than its factorization.
12521126066350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14256901 (or 14256896 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 40.
Adding to 12521126066350 its reverse (5366062112521), we get a palindrome (17887188178871).
The spelling of 12521126066350 in words is "twelve trillion, five hundred twenty-one billion, one hundred twenty-six million, sixty-six thousand, three hundred fifty".
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