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12521311305149 is a prime number
BaseRepresentation
bin1011011000110101100001…
…0011111111110110111101
31122100000200201021021210002
42312031120103333312331
53120122121143231044
642344113324324045
72431430524003013
oct266153023776675
948300621237702
1012521311305149
113a98292890289
1214a28699a3625
136ca9a6aaab9a
1431406b30c8b3
1516aa9499474e
hexb63584ffdbd

12521311305149 has 2 divisors, whose sum is σ = 12521311305150. Its totient is φ = 12521311305148.

The previous prime is 12521311305079. The next prime is 12521311305163. The reversal of 12521311305149 is 94150311312521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8863463802649 + 3657847502500 = 2977157^2 + 1912550^2 .

It is a cyclic number.

It is not a de Polignac number, because 12521311305149 - 232 = 12517016337853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12521311305649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6260655652574 + 6260655652575.

It is an arithmetic number, because the mean of its divisors is an integer number (6260655652575).

Almost surely, 212521311305149 is an apocalyptic number.

It is an amenable number.

12521311305149 is a deficient number, since it is larger than the sum of its proper divisors (1).

12521311305149 is an equidigital number, since it uses as much as digits as its factorization.

12521311305149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 38.

The spelling of 12521311305149 in words is "twelve trillion, five hundred twenty-one billion, three hundred eleven million, three hundred five thousand, one hundred forty-nine".