Base | Representation |
---|---|
bin | 1011011000110101100001… |
… | …0011111111110110111101 |
3 | 1122100000200201021021210002 |
4 | 2312031120103333312331 |
5 | 3120122121143231044 |
6 | 42344113324324045 |
7 | 2431430524003013 |
oct | 266153023776675 |
9 | 48300621237702 |
10 | 12521311305149 |
11 | 3a98292890289 |
12 | 14a28699a3625 |
13 | 6ca9a6aaab9a |
14 | 31406b30c8b3 |
15 | 16aa9499474e |
hex | b63584ffdbd |
12521311305149 has 2 divisors, whose sum is σ = 12521311305150. Its totient is φ = 12521311305148.
The previous prime is 12521311305079. The next prime is 12521311305163. The reversal of 12521311305149 is 94150311312521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8863463802649 + 3657847502500 = 2977157^2 + 1912550^2 .
It is a cyclic number.
It is not a de Polignac number, because 12521311305149 - 232 = 12517016337853 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12521311305649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6260655652574 + 6260655652575.
It is an arithmetic number, because the mean of its divisors is an integer number (6260655652575).
Almost surely, 212521311305149 is an apocalyptic number.
It is an amenable number.
12521311305149 is a deficient number, since it is larger than the sum of its proper divisors (1).
12521311305149 is an equidigital number, since it uses as much as digits as its factorization.
12521311305149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 38.
The spelling of 12521311305149 in words is "twelve trillion, five hundred twenty-one billion, three hundred eleven million, three hundred five thousand, one hundred forty-nine".
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