Base | Representation |
---|---|
bin | 10010001110001111100… |
… | …001101000001000000011 |
3 | 11102201020222221211220112 |
4 | 102032033201220020003 |
5 | 131004043310041011 |
6 | 2355134522501535 |
7 | 156320521421405 |
oct | 22161741501003 |
9 | 4381228854815 |
10 | 1252243440131 |
11 | 4430898599a2 |
12 | 1828399648ab |
13 | 911170886a8 |
14 | 44874ba2b75 |
15 | 228914cd58b |
hex | 1238f868203 |
1252243440131 has 2 divisors, whose sum is σ = 1252243440132. Its totient is φ = 1252243440130.
The previous prime is 1252243440073. The next prime is 1252243440163. The reversal of 1252243440131 is 1310443422521.
It is an a-pointer prime, because the next prime (1252243440163) can be obtained adding 1252243440131 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1252243440131 - 238 = 977365533187 is a prime.
It is a super-2 number, since 2×12522434401312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1252243443131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626121720065 + 626121720066.
It is an arithmetic number, because the mean of its divisors is an integer number (626121720066).
Almost surely, 21252243440131 is an apocalyptic number.
1252243440131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252243440131 is an equidigital number, since it uses as much as digits as its factorization.
1252243440131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 1252243440131 its reverse (1310443422521), we get a palindrome (2562686862652).
The spelling of 1252243440131 in words is "one trillion, two hundred fifty-two billion, two hundred forty-three million, four hundred forty thousand, one hundred thirty-one".
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