Base | Representation |
---|---|
bin | 1011011000111100010000… |
… | …1100110000000111001101 |
3 | 1122100012100212011211122002 |
4 | 2312033010030300013031 |
5 | 3120134323031014343 |
6 | 42345013104002045 |
7 | 2431523423044031 |
oct | 266170414600715 |
9 | 48305325154562 |
10 | 12523121344973 |
11 | 3a99031581a68 |
12 | 14a3094000325 |
13 | 6cac04aa4975 |
14 | 31419d87a1c1 |
15 | 16ab4d8328b8 |
hex | b63c43301cd |
12523121344973 has 2 divisors, whose sum is σ = 12523121344974. Its totient is φ = 12523121344972.
The previous prime is 12523121344967. The next prime is 12523121345057. The reversal of 12523121344973 is 37944312132521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11190985255849 + 1332136089124 = 3345293^2 + 1154182^2 .
It is a cyclic number.
It is not a de Polignac number, because 12523121344973 - 28 = 12523121344717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12523121344913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6261560672486 + 6261560672487.
It is an arithmetic number, because the mean of its divisors is an integer number (6261560672487).
Almost surely, 212523121344973 is an apocalyptic number.
It is an amenable number.
12523121344973 is a deficient number, since it is larger than the sum of its proper divisors (1).
12523121344973 is an equidigital number, since it uses as much as digits as its factorization.
12523121344973 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1088640, while the sum is 47.
The spelling of 12523121344973 in words is "twelve trillion, five hundred twenty-three billion, one hundred twenty-one million, three hundred forty-four thousand, nine hundred seventy-three".
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